Question

Tìm số nguyên x:

(x + 2).(x - 3)= 0

Answer 1

Ta có: (x+2)(x-3)=0

\(\Leftrightarrow\left[{}\begin{matrix}x+2=0\\x-3=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-2\\x=3\end{matrix}\right.\)

Vậy: \(x\in\left\{-2;3\right\}\)

Answer 2

(x + 2)(x - 3) = 0  (x \(\in\) Z)

\(\Rightarrow\) x + 2 = 0 hoặc x - 3 = 0

Xét các trường hợp:

+) TH1: x + 2 = 0

\(\Rightarrow\) x = -2 (TM)

+) TH2: x - 3 = 0

\(\Rightarrow\) x = 3 (TM)

Vậy x = -2; x = 3

Chúc bn học tốt!

Answer 3

(x+2).(x-3)=0

\(\Rightarrow\left[{}\begin{matrix}x+2=0\\x-3=0\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=0-2=-2\\x=0+3=3\end{matrix}\right.\) 

Vậy x \(\in\left\{-2;3\right\}\)

Answer 4

\(\Leftrightarrow\left\{{}\begin{matrix}x+2=0\\X-3=0\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}x=-2\\x=3\end{matrix}\right.\)