\(f\left(x\right)=1\Leftrightarrow x^2-1=1\) \(\Leftrightarrow x^2=2\)\(\Leftrightarrow\left[{}\begin{matrix}x=-\sqrt{2}\\x=\sqrt{2}\end{matrix}\right.\).
Giải:
Vì \(f\left(x\right)=1.\)
\(\Rightarrow x^2-1=1.\)
\(\Rightarrow x^2=2.\)
\(\Leftrightarrow x=\left[{}\begin{matrix}\sqrt{2}.\\-\sqrt{2}.\end{matrix}\right.\)
Vậy \(x=\left\{\sqrt{2};-\sqrt{2}\right\}.\)