mình ko biết đúng hay sai các bạn nếu thấy mình sai thì các bạn sửa hộ mình
ta có \(\dfrac{a}{c}=\dfrac{c}{b}=>ab=c^2\)
=>\(\dfrac{b^2-a^2}{a^2+c^2}=\dfrac{b^2-ab+ab-a^2}{a^2+ab}=\dfrac{b.\left(b-a\right)+a.\left(b-a\right)}{a.\left(a+b\right)}=\dfrac{\left(b+a\right).\left(b-a\right)}{a.\left(a+b\right)}=\dfrac{b-a}{a}=>ĐPCM\)
\(Cho\dfrac{a}{b}=\dfrac{c}{d}CMR\left(\dfrac{a+b}{c+d}\right)^2=\dfrac{a^2-b^2}{c^2-d^2}\)
Cho \(\dfrac{a}{b}=\dfrac{c}{d}\)và b, d khác 0. CMR \(\dfrac{ac}{bd}=\dfrac{a^2+c^2}{b^2+d^2}\)
Cho \(\dfrac{a}{b}=\dfrac{c}{d}\). CMR: \(\dfrac{ab}{cd}=\dfrac{a^2+b^2}{c^2+d^2}\)
Các bạn giúp mình với ạ!
Bài 1 Cho \(\dfrac{a+b+c}{a+b-c}=\dfrac{a-b+c}{a-b-c}\left(b\ne0\right)\) CMR \(c=0\)
Bài 2 Cho \(\dfrac{a}{b}=\dfrac{b}{c}=\dfrac{c}{d}CMR\left(\dfrac{a+b+c}{b+c+d}\right)^3=\dfrac{a}{d}\)
Cho tỉ lệ thức \(\dfrac{a}{b}=\dfrac{c}{d}\)
CMR \(\dfrac{ab}{cd}=\dfrac{a^2-b^2}{c^2-d^2}\) và \(\left(\dfrac{a+b}{c+d}\right)^2=\dfrac{a^2+b^2}{c^2+d^2}\)
Cho \(\dfrac{a}{b}=\dfrac{c}{d}.CMR\)
a, \(\dfrac{2a+3b}{2a-3b}=\dfrac{2c+3d}{2c-3d}\)
b, \(\dfrac{ab}{cd}=\dfrac{a^2-b^2}{c^2-d^2}\)
c, \(\dfrac{\left(a+b\right)^2}{\left(c+d\right)^2}=\dfrac{a^2+b^2}{c^2+d^2}\)
Cho tỉ lệ thức \(\dfrac{a}{b}\)=\(\dfrac{c}{d}\) Chứng minh:
1)\(\dfrac{a-b}{b}\)=\(\dfrac{c-d}{d}\) 2)\(\dfrac{a-b}{a}\)=\(\dfrac{c-d}{c}\)
giải giúp mk vss
1)Cho tỉ lệ thức : \(\dfrac{\overline{abc}}{a+\overline{bc}}=\dfrac{\overline{bca}}{b+\overline{ca}}\) . Chứng minh \(\dfrac{a}{\overline{bc}}=\dfrac{b}{\overline{ca}}\)
2)Cho a, b , c \(\ne0\) , \(\dfrac{a+b-c}{c}=\dfrac{b+c-a}{a}=\dfrac{c+a-b}{b}\)
Tính P = \(\left(1+\dfrac{b}{a}\right).\left(1+\dfrac{c}{b}\right).\left(1+\dfrac{a}{b}\right)\)
Mấy bợn làm nhanh hộ mình nha !!! Mai mình đi học nhưng vẫn chưa làm đc . Ai làm đc thì làm cấp tốc hộ mình nhé !!! Cảm ơn nhiều !!!
cho \(\dfrac{a}{b}\) =\(\dfrac{c}{d}\) cm rằng
a) \(\dfrac{a}{a-b}\) =\(\dfrac{c}{c-d}\) b)\(\dfrac{a}{b}\) =\(\dfrac{a+c}{b+d}\) c) \(\dfrac{a}{3a+d}\) =\(\dfrac{c}{3c+d}\) d)\(\dfrac{a.c}{b.d}\) =\(\dfrac{a^2+c^2}{b^2+c^2}\) e)\(\dfrac{a.b}{c.d}\) =\(\dfrac{a^2-b^2}{c^2-d^2}\) f)\(\dfrac{a.b}{c.d}\) =\(\dfrac{\left(a-b\right)^2}{\left(c-d\right)^2}\)
mn giúp mk vs ạ! thanks
