a: ĐKXĐ: \(x\notin\left\{\dfrac{2}{3};-\dfrac{2}{3}\right\}\)
\(A=\dfrac{3x-2+3x+2}{\left(3x+2\right)\left(3x-2\right)}\cdot\dfrac{3x+2}{1}=\dfrac{6x}{3x-2}\)
b: Để A là số nguyên thì \(6x-4+4⋮3x-2\)
\(\Leftrightarrow3x-2\in\left\{1;-1;2;-2;4;-4\right\}\)
hay \(x\in\left\{1;\dfrac{1}{3};\dfrac{4}{3};0;2\right\}\)