Theo BĐT tam giác ta có:
\(\left\{{}\begin{matrix}a< b+c\\b< a+c\\c< a+b\end{matrix}\right.\)\(\Rightarrow\left\{{}\begin{matrix}a^2< ab+ac\\b^2< ab+bc\\c^2< ac+bc\end{matrix}\right.\)
\(\Rightarrow a^2+b^2+c^2< ab+bc+ca+ab+bc+ca\)
\(\Leftrightarrow a^2+b^2+c^2< 2\left(ab+bc+ca\right)\)