\(n_{HCl}=0.2\cdot0.5=0.1mol\)
a, PT: \(Fe+2HCl\rightarrow FeCl_2+H_2\)
0,05mol\(\leftarrow\)0.1 mol\(\rightarrow\) 0.05 mol\(\rightarrow\) 0.05mol
b, \(a=m_{Fe}=0.05\cdot56=2.8\left(g\right)\)
c, \(V_{H2}=n\cdot22.4=0.05\cdot22.4=1.12\left(l\right)\)
d, \(m_{FeCl2}=0.05\cdot127=6.35\left(g\right)\)