\(P=2a+\dfrac{9}{a}+3b+\dfrac{2}{b}=\left(a+\dfrac{9}{a}\right)+\left(2b+\dfrac{2}{b}\right)+\left(a+b\right)\)
\(\ge2\sqrt{a.\dfrac{9}{a}}+2\sqrt{2b.\dfrac{2}{b}}+=6+4+4=14\)
Dấu "=" xảy ra \(\Leftrightarrow\left\{{}\begin{matrix}a=3\\b=1\end{matrix}\right.\)