\(\Leftrightarrow\dfrac{a^2+b^2+c^2}{3}>=\dfrac{\left(a+b+c\right)^2}{9}\)
\(\Leftrightarrow3a^2+3b^2+3c^2>=a^2+b^2+c^2+2ab+2ac+2bc\)
\(\Leftrightarrow2a^2+2b^2+2c^2-2ba-2ac-2bc>=0\)
\(\Leftrightarrow\left(a-b\right)^2+\left(b-c\right)^2+\left(a-c\right)^2>=0\)(luôn đúng)