\(2x+2y\le1\Rightarrow x+y\le\frac{1}{2}\Rightarrow2\sqrt{xy}\le x+y\le\frac{1}{2}\)
\(\Rightarrow\sqrt{xy}\le\frac{1}{4}\Rightarrow xy\le\frac{1}{16}\Rightarrow\frac{1}{xy}\ge16\)
\(P=xy+\frac{1}{256xy}+\frac{255}{256xy}\ge2\sqrt{\frac{xy}{256xy}}+\frac{255}{256}.16=\frac{257}{16}\)
\(\Rightarrow P_{min}=\frac{257}{16}\) khi \(x=y=\frac{1}{4}\)