Thế méo nào cho lẻ độ @@
Giả sử \(\widehat{xOz}+\widehat{yOz}+\widehat{yOt}=250^o46'\)
mà \(\widehat{xOz}+\widehat{yOz}=180^o\)
\(\Rightarrow\widehat{yOt}=250^o46'-180^o=70^o46'\)
Mặt khác \(\widehat{yOt}=\widehat{xOz}\left(d.d\right)\Rightarrow\widehat{yOt}=\widehat{xOz}=70^o46'\)
Ta có:
\(\widehat{yOt}+\widehat{yOz}=180^o\Rightarrow\widehat{yOz}=180^o-70^o46'=109^o14'\)
mà \(\widehat{yOz}=\widehat{xOt}\left(d.d\right)\Rightarrow\widehat{yOz}=\widehat{xOt}=109^o14'\)
Vậy...........
Chúc bạn học tốt!!!