a) 2Al+6HCl----->2AlCl3+3H2
x-----------3x------------------1,5x
K2CO3+2HCl--->2KCl+H2O+CO2
x------------2x-----------------------x
b) n khí =0,4(mol)
Theo bài ra ta có pt
\(\)\(\left\{{}\begin{matrix}27x+138y=19,2\\1,5x+y=0,4\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=0,2\\y=0,1\end{matrix}\right.\)
%m Al=\(\frac{0,2.27}{19,2}.100\%=28,125\left(mol\right)\)
%m\(_{K2CO3}=100-28,125=71,825\left(mol\right)\)
b) Theo pthh
n\(_{HCl}=2nkhí=0,8\left(mol\right)\)
C%=\(\frac{0,8.36,5}{100}.100\%=29,2\%\)
