Câu 1 : Thực hiện phép tính
a) \(\sqrt{0,36.100}=\sqrt{36.1}=\sqrt{36}.\sqrt{1}=6.1=6\)
b) \(^3\sqrt{-0,008}=^3\sqrt{\left(-0.2\right)^3}=-0,2\)
c) \(\sqrt{12}+6\sqrt{3}+\sqrt{27}=2\sqrt{3}+6\sqrt{3}+3\sqrt{3}=11\sqrt{3}\)
a/ \(\sqrt{0,36.100}=\sqrt{36}=\sqrt{6^2}=6\)
b/ \(\sqrt[3]{-0,008}=\sqrt[3]{-\dfrac{8}{1000}}=\sqrt[3]{-\left(\dfrac{2}{10}\right)^3}=-\dfrac{2}{10}=-0,2\)
c/ \(\sqrt{12}+6\sqrt{3}+\sqrt{27}\) = \(2\sqrt{3}+6\sqrt{3}+3\sqrt{3}=11\sqrt{3}\)