\(2\left(x-3\right)-3\left(1-2x\right)=4+4\left(1-x\right)\)
\(\Rightarrow2x-6-3+6x=4+4-4x\)
\(\Rightarrow2x+6x+4x=4+4+3+6\)
\(\Rightarrow12x=17\Rightarrow x=\dfrac{17}{12}\)
Vậy..................
\(2\left(x-3\right)-3\left(1-2x\right)=4+4\left(1-x\right)\)
\(2x-6-3+6x=4+4-4x\)
\(8x-9=8-4x\)
\(8x=8-4x+9\)
\(8x=17-4x\)
\(12x=17\)
\(x=\dfrac{17}{12}\)