Giải:
a) Ta có:
\(-2< 0\)
\(\Leftrightarrow-\dfrac{2}{3}< \dfrac{0}{3}\)
\(\Leftrightarrow-\dfrac{2}{3}< 0\)
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b) Ta có:
\(\dfrac{2002}{2003}=\dfrac{2003}{2003}-\dfrac{1}{2003}=1-\dfrac{1}{2003}< 1\)
\(\dfrac{14}{13}=\dfrac{13}{13}+\dfrac{1}{13}=1+\dfrac{1}{13}>1\)
\(\Leftrightarrow\dfrac{2002}{2003}< 1< \dfrac{14}{13}\)
\(\Leftrightarrow\dfrac{2002}{2003}< \dfrac{14}{13}\)
Vậy ...