2a-b=5 nên b=2a-5
\(A=\dfrac{7a-2b}{3a+10}-\dfrac{7b-4a}{15b-30}\)
\(=\dfrac{7a-2\left(2a-5\right)}{3a+10}-\dfrac{7\left(2a-5\right)-4a}{15\left(2a-5\right)-30}\)
\(=\dfrac{7a-4a+10}{3a+10}-\dfrac{14a-35-4a}{30a-75-30}\)
\(=1-\dfrac{5\left(2a-7\right)}{15\left(2a-7\right)}=1-\dfrac{1}{3}=\dfrac{2}{3}\)