\(x^2-4x+4m+3\le0\)
\(\Delta'=1-4m>0\Rightarrow m< \frac{1}{4}\)
Theo định lý Viet: \(\left\{{}\begin{matrix}x_1+x_2=4\\x_1x_2=4m+3\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x_1+x_2=4\\x_1^5-x_2=-2\end{matrix}\right.\) \(\Rightarrow x_1^5+x_1-2=0\)
\(\Rightarrow x_1=1\Rightarrow x_2=3\)
\(\Rightarrow m=\frac{x_1x_2-3}{4}=0\)