Question

Bài 4 tính hợp lí 

\(\dfrac{3}{5}+\dfrac{3}{11}-\left(\dfrac{-3}{7}\right)+\left(\dfrac{-2}{97}\right)-\dfrac{1}{35}-\dfrac{3}{4}+\left(\dfrac{-23}{44}\right)\)

 

giải giúp

Answer 1

\(=\left(\dfrac{3}{5}-\dfrac{-3}{7}-\dfrac{1}{35}\right)+\left(\dfrac{3}{11}-\dfrac{3}{4}+\dfrac{-23}{44}\right)+\dfrac{-2}{97}\)

\(=\left(\dfrac{21}{35}+\dfrac{25}{35}-\dfrac{1}{35}\right)+\left(\dfrac{12}{44}-\dfrac{33}{44}-\dfrac{23}{44}\right)-\dfrac{2}{97}\)

\(=\dfrac{9}{7}+\left(-1\right)-\dfrac{2}{97}\)

\(=\dfrac{9}{7}-1-\dfrac{2}{97}\)

\(=\dfrac{873}{679}-\dfrac{679}{679}-\dfrac{14}{679}\)

\(=\dfrac{180}{679}\)

Answer 2

\(=\dfrac{3}{5}+\dfrac{3}{11}+\dfrac{3}{7}-\dfrac{2}{97}-\dfrac{1}{35}-\dfrac{3}{4}-\dfrac{23}{44}\)
\(=\dfrac{35}{35}+\dfrac{-44}{44}-\dfrac{2}{97}=\left(1-1\right)-\dfrac{2}{97}=\dfrac{-2}{97}\)