a) \(f\left(x\right)=x^2-2x-5x^4+6\)
\(=-5x^4+x^2-2x+6\)
\(g\left(x\right)=x^3-5x^4+3x^2-3\)
\(=-5x^4+x^3+3x^2-3\)
b) \(f\left(x\right)+g\left(x\right)=-5x^4+x^2-2x+6-5x^4+x^3+3x^2-3\)
\(=-10x^4+4x^2+x^3-2x+3\)
\(f\left(x\right)-g\left(x\right)=-5x^4+x^2-2x+6+5x^4-x^3-3x^2+3\)
\(=-2x^2-x^3-2x+9\)
c) Thay x = 1 vào f(x) ta có:
\(f\left(1\right)=1-2-5+6=0\)
Vậy x = 1 là nghiệm của f(x)
d) \(h\left(x\right)+f\left(x\right)-g\left(x\right)=-2x^2-x+9\)
\(\Rightarrow h\left(x\right)=-2x^2-x+9+g\left(x\right)-f\left(x\right)\)
\(\Rightarrow h\left(x\right)=-2x^2-x+9+2x^2+x^3+2x-9\)
\(\Rightarrow h\left(x\right)=x^3+x\)
e) Ta có: \(x^3+x=0\)
\(\Rightarrow x^2\left(x+1\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x^2=0\\x+1=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=0\\x=-1\end{matrix}\right.\)
Vậy x = 0, x = -1 là nghiệm của H(x)