\(\left|x-2y\right|=5\Leftrightarrow\left[{}\begin{matrix}x-2y=5\\x-2y=-5\end{matrix}\right.\)
Ta có:
\(2x=3y=5z\Leftrightarrow\dfrac{2x}{30}=\dfrac{3y}{30}=\dfrac{5z}{30}\)
\(\Rightarrow\dfrac{x}{15}=\dfrac{y}{10}=\dfrac{z}{6}\)
\(\Rightarrow\dfrac{x}{15}=\dfrac{2y}{20}=\dfrac{z}{6}\)
Áp dụng dãy tỉ số bằng nhau..........