Question

Bài 1: Thực hiện phép tính:

a) A = [6.(^{\(\dfrac{1}{3}\)})³- 3 (-\(\dfrac{1}{3}\))+ 1 ] : (-\(\dfrac{1}{3}\)-1)

b) B = \(\dfrac{\dfrac{1}{39}-\dfrac{1}{6}-\dfrac{1}{51}}{\dfrac{1}{8}-\dfrac{1}{52}+\dfrac{1}{68}}:5\dfrac{1}{6}\)

Answer 1

a: \(A=\left[6\cdot\dfrac{1}{27}+3\cdot\dfrac{1}{3}+1\right]:\dfrac{-4}{3}\)

\(=\left(\dfrac{2}{9}+2\right)\cdot\dfrac{-3}{4}\)

\(=\dfrac{20}{9}\cdot\dfrac{-3}{4}=\dfrac{-60}{36}=\dfrac{-5}{3}\)

b: \(B=\dfrac{\dfrac{1}{3}\left(\dfrac{1}{13}-\dfrac{1}{2}-\dfrac{1}{17}\right)}{-\dfrac{1}{4}\left(\dfrac{1}{13}-\dfrac{1}{2}-\dfrac{1}{17}\right)}:\dfrac{11}{6}\)

\(=\dfrac{-1}{3}:\dfrac{1}{4}\cdot\dfrac{6}{11}=\dfrac{-4}{3}\cdot\dfrac{6}{11}=\dfrac{-24}{33}=\dfrac{-8}{11}\)