\(Q=\frac{1}{a+ab+1}+\frac{1}{b+bc+1}+\frac{1}{c+ac+1}\)
\(=\frac{1.c}{\left(a+ab+1\right)c}+\frac{1.ac}{\left(b+bc+1\right).ac}+\frac{1}{c+ac+1}\)
\(=\frac{c}{ac+abc+c}+\frac{ac}{abc+abc^2+ac}+\frac{1}{c+ac+1}\)
\(=\frac{c}{ac+1+c}+\frac{ac}{1+c+ac}+\frac{1}{c+ac+1}\)
\(=\frac{c+ac+1}{c+ac+1}=1\)