Question

bài 1:

a) (\(-\dfrac{1}{2}\))³ + (\(\dfrac{5}{6}\))⁰ - (\(-\dfrac{3}{2}\))²-(-1)¹⁰

b) 4(\(-\dfrac{1}{3}\))⁰ - 2(\(-\dfrac{1}{2}\))²+3(\(-\dfrac{1}{2}\))+1

Bài 2:

a)(4x - 3)^x=-125

Answer 1

Bài 1: 

a: \(=\dfrac{-1}{8}+1-\dfrac{9}{4}-1\)

\(=\dfrac{-1}{8}-\dfrac{18}{8}=\dfrac{-19}{8}\)

b: \(=4\cdot1-2\cdot\dfrac{1}{4}+3\cdot\dfrac{-1}{2}+1\)

\(=4-\dfrac{1}{2}-\dfrac{3}{2}+1\)

=5-2

=3