\(\frac{1-3x}{2x}+\frac{3x-2}{2x-1}+\frac{3x-2}{2x-4x^2}\)
\(=\frac{\left(1-3x\right)\left(2x-1\right)+2x\left(3x-2\right)+2-3x}{2x\left(2x-1\right)}\)
\(=\frac{2x-1-6x^2+3x+6x^2-4x+2-3x}{2x\left(2x-1\right)}\)
\(=\frac{-2x+1}{2x\left(x-1\right)}\)
\(=-\frac{1}{2x}\)
b ) \(\frac{1-3x}{2x}+\frac{3x-2}{2x-1}+\frac{3x-2}{2x-4x^2}\)
Giải Phương trình
a) (5,5-11x)(\(\frac{7x+2}{5}\)+ (\(\frac{2\left(1-3x\right)}{3}\))= 0
b) (2x=3)(3x-1)= (2x+3)(x-2)
c) (4-3x)(2x+3)=(5-2x)(3x-4)
d) (3x^2+1)(4x-3)= (3x^2+1)(x-7)
\(\frac{1-3x}{2x}+\frac{3x-2}{2x-1}+\frac{3x-2}{2x-4x^2}\)
Rút gọn
a)\(\frac{3}{2x+6}-\frac{x-6}{2x^2+6x}\)
b)\(\left\{\frac{2x+1}{2x-1}-\frac{2x-1}{2x+1}\right\}:\frac{4x}{10x-5}\)
c)\(\frac{x^2+x}{5x^2-10x+5}:\frac{3x+3}{5x-5}\)
Rút gọn A : \(\left[\frac{\left(x-1\right)^2}{3x+\left(x-1\right)^2}-\frac{1-2x^2+4x}{x^3-1}+\frac{1}{x-1}\right]:\frac{2x}{x^3+x}\)
giúp mình với
làm phép tính
c) \(\frac{1}{3x-2}-\frac{4}{3x+2}-\frac{3x-6}{4-9x^2}\)
d) x - 2 \(-\frac{x^2-10}{x+2}\)
e)\(\frac{1}{2x-2y}-\frac{1}{2x+2y}+\frac{y}{y^2-x^2}\)
g)\(\frac{4-2x+x^2}{x+2}-2-x\)
i)\(\frac{1}{2x+3}-\frac{1}{2x-3}+\frac{x-2}{2x^2-x-3}\)
1/\(\frac{4x^2-3x+5}{x^3-1}\) , \(\frac{1-2x}{x^2+x+1}\) , \(\frac{-2}{1}\)
2/\(\frac{1}{x+2}\) , \(\frac{8}{2x-x^2}\)
3/\(\frac{2x}{x^2-8x+16}\) , \(\frac{x}{3x^2-12x}\)
4/\(\frac{7x-1}{2x^2+6x}\) , \(\frac{5-3x}{x^2-9}\)
Quy đồng phân thức
Giải phương trình
a) \(\frac{2}{x+\frac{1}{1+\frac{x+1}{x-2}}}=\frac{6}{3x-1}\)
b) \(\frac{3x-1}{x-1}-\frac{2x+2}{x+2}+\frac{4}{x^2+2x-3}=1\)
1) Dùng định nghĩa 2 phân thức = nhau tìm đa thức A trong mỗi trường hợp sau :
a) \(\frac{x^2+5x+4}{x^2-1}=\frac{A}{x^2-2x+1}\)
b)\(\frac{x^2-3x}{2x^2-7x+3}=\frac{x^2+4x}{A}\)
