a,\(\sqrt{22+12\sqrt{2}}\)
b,\(\sqrt{\dfrac{5+2\sqrt{6}}{2}}\)
c,\(\sqrt{30+4\sqrt{2}\sqrt{7}}\)
d,\(\sqrt{5+2\sqrt{2-\sqrt{9-4\sqrt{2}}}}\)
e,\(\sqrt{1+2\sqrt{\sqrt{2+\sqrt{11+6\sqrt{2}}}}}\)
f,\(\sqrt{1+\dfrac{\sqrt{3}}{2}+\sqrt{1-\dfrac{\sqrt{3}}{2}}}\)
g,\(\sqrt{10-2\sqrt{21}}+\sqrt{4+2\sqrt{3}}\)
a,\(\sqrt{2\left(11+6\sqrt{2}\right)}\)=\(\sqrt{2\left(9+2.3.\sqrt{2}+2\right)}\)=\(\sqrt{2\left(3+\sqrt{2}\right)^2}\)=\(\sqrt{2}\)(3+\(\sqrt{2}\))
\(a.\sqrt{22+12\sqrt{2}}=\sqrt{18+2.3\sqrt{2}.2+4}=3\sqrt{2}+2\)
\(b.\sqrt{\dfrac{5+2\sqrt{6}}{2}}=\sqrt{\dfrac{3+2\sqrt{3}.\sqrt{2}+2}{2}}=\dfrac{\sqrt{3}+\sqrt{2}}{2}\)
\(c.\sqrt{30+4\sqrt{2}.\sqrt{7}}=\sqrt{28+2.\sqrt{2}.2\sqrt{7}+2}=2\sqrt{7}+\sqrt{2}\)
\(d.\sqrt{5+2\sqrt{2-\sqrt{9-4\sqrt{2}}}}=\sqrt{5+2\sqrt{2-\sqrt{8-2.2\sqrt{2}+1}}}=\sqrt{5+2\sqrt{2-2\sqrt{2}+1}}=\sqrt{2+2\sqrt{2}+1}=\sqrt{2}+1\) \(e.\sqrt{1+2\sqrt{\sqrt{2+\sqrt{11+6\sqrt{2}}}}}=\sqrt{1+2\sqrt{\sqrt{2+\sqrt{9+2.3\sqrt{2}+2}}}}=\sqrt{1+2\sqrt{\sqrt{5+\sqrt{2}}}}\)
\(f.\sqrt{1+\dfrac{\sqrt{3}}{2}+\sqrt{1-\dfrac{\sqrt{3}}{2}}}=\sqrt{1+\dfrac{\sqrt{3}}{2}+\sqrt{\dfrac{3}{4}-2.\dfrac{\sqrt{3}}{2}.\dfrac{1}{2}+\dfrac{1}{4}}}=\sqrt{\sqrt{3}+\dfrac{1}{2}}=\)
\(g.\sqrt{10-2\sqrt{21}}+\sqrt{4+2\sqrt{3}}=\sqrt{7-2\sqrt{7}.\sqrt{3}+3}+\sqrt{3+2\sqrt{3}+1}=\sqrt{7}-\sqrt{3}+\sqrt{3}+1=\sqrt{7}+1\)
b, \(\sqrt{\dfrac{2+2.\sqrt{2}.\sqrt{3}+3}{2}}\) =\(\sqrt{\dfrac{\left(\sqrt{2}+\sqrt{3}\right)^2}{2}}\) =\(\dfrac{\sqrt{2}+\sqrt{3}}{\sqrt{2}}\)
mấy câu này là mình nghĩ đề bài là rút gọn nhé =))))
đề bài khác thì thôi :())(
c,
\(\sqrt{30+4.\sqrt{14}}\) =\(\sqrt{2}\).\(\sqrt{14+2.\sqrt{14}.1+1}\) =..................
giống câu a, nha
g,
\(\sqrt{\left(\sqrt{7}-\sqrt{3}\right)^2}\) +\(\sqrt{\left(\sqrt{3}+1\right)^2}\)
\(\sqrt{7}\) -\(\sqrt{3}\) +\(\sqrt{3}\)+1
\(\sqrt{7}\)+1
