\(A=\left(\dfrac{5.5^3}{125^2.49}\right)^{15}:\left(\dfrac{5^6}{434}\right)^7\)
\(=\left(\dfrac{5^4}{5^6.7^2}\right)^{15}.\dfrac{434^7}{5^{42}}\)
\(=\left(\dfrac{1}{5^2.7^2}\right)^{15}.\dfrac{434^7}{5^{42}}\)
\(=\dfrac{62^7.7^7}{5^{30}.7^{30}.5^{42}}\)
\(=\dfrac{62^7}{5^{72}.7^{23}}\)
Tuấn Anh Phan Nguyễn ( tui k giỏi = ông , lm ik )
Đoàn Đức Hiếu ( pé lm hộ cj nha , cj đag hc lại lp 4 )
434 hay là 343 vậy nếu là 343 thì pé ra
\(\dfrac{5^{12}}{7^{33}}\)
Có cần ra kết quả cụ thể VD như 142 hay 2453 không hay chỉ cần như kiểu \(\dfrac{x^n}{y^m}\)
\(A=\left(\dfrac{5\cdot5^3}{125^2\cdot49}\right)^{15}\cdot\left(\dfrac{5^6}{434}\right)^7\)
\(=\dfrac{5\cdot5^{45}}{\left(125^2\cdot49\right)^{15}}\cdot\dfrac{5^{42}}{434^7}\)
\(=\dfrac{\left(\dfrac{11}{2}\right)^{45}}{\left(\left(5^3\right)^2\cdot49\right)^{15}}\cdot\dfrac{5^{42}}{434^7}\)
\(=\dfrac{\dfrac{11^{45}}{2^{45}}}{\left(5^6\cdot49\right)^{15}}\cdot\dfrac{5^{42}}{434^7}\)
\(=\dfrac{\dfrac{11^{45}}{2^{45}}}{5^{90}\cdot49^{15}}\cdot\dfrac{5^{42}}{434^7}\)
\(=\dfrac{11^{45}}{2^{45}\cdot5^{90}\cdot49^{15}}\cdot\dfrac{5^{42}}{434^7}\)
\(=\dfrac{11^{45}}{2^{45}\cdot5^{48}\cdot49^5}\cdot\dfrac{1}{434^7}\)
\(=\dfrac{11^{45}}{2^{45}\cdot5^{48}\cdot49^{15}\cdot434^7}\)
\(=0\)
Sửa đề:
\(A=\left(\dfrac{5.5^3}{125^2.49}\right)^{15}:\left(\dfrac{5^6}{343}\right)^7\)
\(A=\left(\dfrac{5^4}{5^6.7^2}\right)^{15}:\left(\dfrac{5^6}{7^3}\right)^7\)
\(A=\left(\dfrac{1}{5^2.7^2}\right)^{15}:\dfrac{5^{42}}{7^{21}}\)
\(A=\dfrac{1}{5^{30}.7^{30}}.\dfrac{7^{21}}{5^{42}}=\dfrac{7^{21}}{5^{30}.7^{30}.5^{42}}\)
\(A=\dfrac{1}{5^{72}.7^9}\)
Em làm thế này không biết có đúng không nữa!
Chúc chị học tốt!!!
