Question

a)IxI+I-xI=3-x

b)\(\frac{x}{6}\)-\(\frac{1}{y}\)=0,5

tính x,y

 

Answer 1

a) \(\left|x\right|\) + \(\left|-x\right|\) = 3 - \(x\) 

\(\Rightarrow\) \(x+x\) = 3 - \(x\) 

\(\Rightarrow\) \(x+x+x\) = 3

\(\Rightarrow\) 3\(x\) = 3

\(\Rightarrow\) \(x\) = 1

Answer 2

b) Ta có : \(\frac{x}{6}\) - \(\frac{1}{y}\) = \(\frac{1}{2}\)  

\(\Rightarrow\) \(\frac{1}{y}\) = \(\frac{x}{6}\) - \(\frac{1}{2}\) 

\(\Rightarrow\) \(\frac{1}{y}\) = \(\frac{x}{6}\) - \(\frac{3}{6}\)

\(\Rightarrow\) \(\frac{1}{y}\) = \(\frac{x-3}{6}\) 

\(\Rightarrow\) 1 . 6 = \(y\)( \(x\) - 3)

\(\Rightarrow\) 6 = \(y\)(\(x\) - 3)

\(\Rightarrow\) \(y\)(\(x\) - 3) ϵ Ư(6)

\(y\)	1	2	3	6	-1	-2	-3	-6
\(x-3\)	6	3	2	1	-6	-3	-2	-1
\(x\)	9	6	5	4	-3	0	1	2