Question

A=\(\dfrac{x-4}{\sqrt{x}+2}+\dfrac{x+2\sqrt{x}}{\sqrt{x}}\)

Answer 1

`A=(x-4)/(\sqrt{x}+2)+(x+2\sqrt{x})/(\sqrt{x})`

`=((\sqrt{x}-2)(\sqrt{x}+2))/(\sqrt{x}+2)+(\sqrt{x}(\sqrt{x}+2))/(\sqrt{x})`

`=\sqrt{x}-2+\sqrt{x}+2`

`=2\sqrt{x}`

Answer 2

\(A=\dfrac{x-4}{\sqrt{x}+2}+\dfrac{x+2\sqrt{x}}{\sqrt{x}}\)

\(A=\dfrac{\left(\sqrt{x}+2\right)\left(\sqrt{x}-2\right)}{\sqrt{x}+2}+\dfrac{\sqrt{x}\left(\sqrt{x}+2\right)}{\sqrt{x}}\)

\(A=\sqrt{x}-2+\sqrt{x}+2\)

\(A=2\sqrt{x}\)