a) \(x+\dfrac{1}{2}=2^5:2^3\)
\(\Rightarrow x+\dfrac{1}{2}=2^{5-3}\)
\(\Rightarrow x+\dfrac{1}{2}=2^2\)
\(\Rightarrow x+\dfrac{1}{2}=4\)
\(\Rightarrow x=4-\dfrac{1}{2}\)
\(\Rightarrow x=\dfrac{7}{2}\)
Vậy \(x=\dfrac{7}{2}\)
b) \(\dfrac{2}{3}+\dfrac{5}{3}x=\dfrac{5}{7}\)
\(\Rightarrow\dfrac{5}{3}x=\dfrac{5}{7}-\dfrac{2}{3}\)
\(\Rightarrow\dfrac{5}{3}x=\dfrac{1}{21}\)
\(\Rightarrow x=\dfrac{1}{21}:\dfrac{5}{3}\)
\(\Rightarrow x=\dfrac{1}{21}.\dfrac{3}{5}\)
\(\Rightarrow x=\dfrac{1}{35}\)
Vậy \(x=\dfrac{1}{35}\)
c) \(\left|x+5\right|-6=9\)
\(\Leftrightarrow\left|x+5\right|=9+6\)
\(\Leftrightarrow\left|x+5\right|=15\)
Xét trường hợp 1: \(x+5=15\)
\(\Rightarrow x=15-5\)
\(\Rightarrow x=10\)
Xét trường hợp 2: \(x+5=-15\)
\(\Rightarrow x=-15-5\)
\(\Rightarrow x=-\left(15+5\right)\)
\(\Rightarrow x=-20\)
Vậy \(x=10\) hoặc \(x=-20\)
