Bài 1:
a. CH4 + 2O2 ---> 2 H2O + CO2
0,2------------0,4--------------------0,2 (mol)
nCH4=\(\dfrac{3,2}{16}\)
a/
Áp dụng công thức: \(m=n.M=>n=\dfrac{m}{M}\)
\(=>n_{CH_4}=\dfrac{m_{CH4}}{M_{CH_4}}=\dfrac{3.2}{16}=0.2\left(mol\right)\)
PTHH:
\(CH_4+2O_2\rightarrow2H_2O+CO_2\)
1 2
0.2 x
\(=>x=0.2\cdot2:1=0.4=n_{O_2}\)
\(=>V_{O_2}=0.4\cdot22.4=8.96\left(l\right)\)