Question

a) \(\left(x+1\right)^3=-27\)

b) \(\sqrt{36}-\sqrt{9}.x=\sqrt{64}\)

Giúp mình với

Answer 1

a)\(\left(x+1\right)^3=-27\)

\(\left(x+1\right)^3=\left(-3\right)^3\)

x+1=-3

x=(-3)-1

x=-4

b)6-3x=8

3x=6-8

3x=(-2)

x=\(-\frac{2}{3}\)

 

 

Answer 2

a) \(\left(x+1\right)^3=-27\)

\(\Rightarrow\left(x+1\right)^3=\left(-3\right)^3\)

\(\Rightarrow x-1=-3\)

\(\Rightarrow x=-4\)

Vậy \(x=-4\)

b) \(\sqrt{36}-\sqrt{9}.x=\sqrt{64}\)

\(\Rightarrow6-3.x=8\)

\(\Rightarrow3x=-2\)

\(\Rightarrow x=\frac{-2}{3}\)

Vậy \(x=\frac{-2}{3}\)