Question

a. \(\sqrt{\left(\sqrt{9-1}\right)^2}\)

b. \(\sqrt{x+3=5}\)

c. \(\sqrt{3x-2}-7=0\)

d. \(\sqrt{2x}=8\)

Answer 1

a) \(\sqrt{\left(\sqrt{9-1}\right)^2}\) = \(\sqrt{8^2}\) = \(\sqrt{64}\) = 8

b) \(\sqrt{x+3}\) = 5 \(\Rightarrow\) \(x\) + 3 = 5² = 25

\(\Rightarrow\) \(x\) = 25 - 3 = 22

c) \(\sqrt{3x-2}\) - 7 = 0 \(\Rightarrow\) \(\sqrt{3x-2}\) = 0 + 7 = 7

\(\Rightarrow\) 3\(x\) - 2 = 7² = 49 \(\Rightarrow\) 3\(x\) = 49 + 2 = 51

\(\Rightarrow\) \(x\) = \(\frac{51}{3}\) = 17

d) \(\sqrt{2x}\) = 8 \(\Rightarrow\) 2\(x\) = 8² = 64 \(\Rightarrow\) \(x\) = \(\frac{64}{2}\) = 32

Answer 2

Ai biết cách làm chỉ mình với

Answer 3

mai đc k bn