Question

a) \(\dfrac{6-x}{3}\)-\(\dfrac{x}{4}\)=\(\dfrac{3+2x}{2}\)-1

b) -7x-\(\dfrac{x-3}{5}\)-\(\dfrac{x}{2}\)=\(x+\dfrac{2x+1}{3}\)

c) \(9-\dfrac{x+3}{2}=-x+\dfrac{1-x}{4}\)

d) \(-\left(x-3\right)-\dfrac{7-2x}{3}=\dfrac{6-x}{5}\)

mn giúp em với ạ,em cảm ơn

Answer 1

a: \(\Leftrightarrow4\left(6-x\right)-3x=6\left(2x+3\right)-12\)

=>24-4x-3x=12x+18-12

=>12x+6=-7x+24

=>19x=18

=>x=18/19

b: \(\Leftrightarrow-210x-6\left(x-3\right)-15x=30x+10\left(2x+1\right)\)

=>-225x-6x+18=30x+20x+10

=>-231x+18-50x-10=0

=>-281x=-8

=>x=8/281

c: \(\Leftrightarrow36-2\left(x+3\right)=-4x+1-x\)

=>36-2x-6=-5x+1

=>3x=1+6-36=5-36=-31

=>x=-31/3

d: \(\Leftrightarrow-30\left(x-3\right)+10\left(2x-7\right)=6\left(6-x\right)\)

=>-30x+90+20x-70=36-6x

=>-10x+20=36-6x

=>-4x=16

=>x=-4