b,\(A=\dfrac{4n+5}{2n+1}=\dfrac{2\left(2n+1\right)+3}{2n+1}\)\(\Rightarrow A=\dfrac{2(2n+1)}{2n+1}+\dfrac{3}{2n+1}\)
\(\Rightarrow A=2+\dfrac{3}{2n+1}\)
=> A nguyên \(\Leftrightarrow\)3\(⋮\)2n+1
=> \(2n+1\inƯ(3)\)
=>Ư(3)\(\in\){\(\pm1;\pm3\)}
Ta có bảng giá trị
2n+1 | 1 | -1 | 3 | -3 |
n | 0 | -1 | 1 | -2 |
=>n thuộc {0;-1;1;-2}
cho mình 1 đúng nha