\(a,1-\left(\dfrac{\dfrac{5}{3}}{8}+x-\dfrac{\dfrac{7}{5}}{24}\right)-\dfrac{\dfrac{16}{2}}{3}=0\\ \Leftrightarrow1-\left(\dfrac{5}{24}+x-\dfrac{7}{120}\right)=\dfrac{8}{3}\\ \Leftrightarrow\dfrac{3}{20}+x=1-\dfrac{8}{3}=-\dfrac{5}{3}\\ \Leftrightarrow x=-\dfrac{5}{3}-\dfrac{3}{20}=-\dfrac{109}{60}\)
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Ta có: \(1-\left(\dfrac{5}{\dfrac{3}{8}}+\dfrac{x-7}{\dfrac{5}{24}}\right)-\dfrac{16}{\dfrac{2}{3}}=0\)
\(\Leftrightarrow\dfrac{40}{3}+\dfrac{24\left(x-7\right)}{5}=23\)
\(\Leftrightarrow\left(x-7\right)\cdot\dfrac{24}{5}=\dfrac{29}{3}\)
\(\Leftrightarrow x-7=\dfrac{145}{72}\)
hay \(x=\dfrac{649}{72}\)
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