\(\left(9x^2-16\right)-x\left(3x-4\right)\)\(=0\)
\(\left(3x-4\right)\left(3x+4\right)-x\left(3x-4\right)\)
\(\left(3x-4\right)\left(3x+4-x\right)\)
3x-4=0 hoặc 3x+4-x=0
3x=4 hoặc 2x+4=0
x=\(\dfrac{4}{3}\) hoặc 2x=-4
x=\(\dfrac{4}{3}\) hoặc x=-2