\(9^{x-1}=9\)
\(\Rightarrow9^{x-1}=9^1\)
\(\Rightarrow x-1=1\)
\(\Rightarrow x=1+1\)
\(\Rightarrow x=2\)
Vậy...
9^(x-1)=9
9=9^1
suy ra 9^(2-1)=9
x=2
9x - 1 = 9
9x - 1 = 91
\(\Rightarrow\) x = 1 + 1
\(\Rightarrow\) x = 2.
9x-1 = 9
9x-1 = 91
=> x - 1 = 1
x = 1 + 1
x = 2
Vậy x = 2