\(\sqrt{9x^2}=2x+1\)
<=> \(\sqrt{\left(3x\right)^2}=2x+1\)
<=> \(|3x|=2x+1\)
<=> \(\left[{}\begin{matrix}3x=-\left(2x+1\right)\\3x=2x+1\end{matrix}\right.\)
<=> \(\left[{}\begin{matrix}3x=-2x-1\\x=1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{-1}{5}\\x=1\end{matrix}\right.\)