Question

81.(27+9¹⁵):(3⁵+3³²)

Answer 1

Answer 2

\(81\cdot\left(27+9^{15}\right):\left(3^5+3^{32}\right)\)

\(=\left(3^4\cdot3^3+3^4\cdot3^{30}\right):\left(3^5+3^{32}\right)\)

\(=\dfrac{3^7+3^{34}}{3^5+3^{32}}\)

\(=\dfrac{3^2\left(3^5+3^{32}\right)}{3^5+3^{32}}=9\)

Answer 3

81.(27 + 915) : (35 + 332) = 34.(33 + 330) : [35(1 + 327)]

= 34.33.(1 + 327) : [35.(1 + 327)]

= 37 : 35 = 37-5 = 32 = 9.