\(5x-4\left(6-x\right)\left(x+3\right)=\left(4-2x\right)\left(3-2x\right)+2\)
\(\Leftrightarrow5x-4\left(18+3x-x^2\right)=12-14x+4x^2+2\)
\(\Leftrightarrow5x-72-12x+4x^2-14+14x-4x^2=0\)
\(\Leftrightarrow7x-86=0\)
\(\Leftrightarrow x=\dfrac{86}{7}\)
\(5x-4\left(6-x\right)\left(x+3\right)=\left(4-2x\right)\left(3-2x\right)+2\\ < =>5x-4\left(6x+18-x^2-3x\right)=\left(12-8x-6x+4x^2\right)+2\)
\(< =>5x-24x-72+4x^2+12x=12-8x-6x+4x^2+2\)
\(< =>4x^2-4x^2+5x-24x+12x+8x+6x=12+2+72\)
\(< =>7x=86\\ < =>x=\dfrac{86}{7}\)
\(5x-4\left(6-x\right)\left(x+3\right)=\left(4-2x\right)\left(3-2x\right)+2\)
\(\Leftrightarrow5x-4\left(6x+18-x^2-3x\right)=\left(12-8x-6x+4x^2\right)+2\)
\(\Leftrightarrow5x-4\left(-x^2+3x+18\right)=4x^2-14x+12+2\)
\(\Leftrightarrow5x+4x^2-12x-72=4x^2-14x+14\)
\(\Leftrightarrow5x+4x^2-12x-72-4x^2+14x-14=0\)
\(\Leftrightarrow7x-86=0\)
\(\Leftrightarrow7x=86\)
\(\Leftrightarrow x=\dfrac{86}{7}\)
\(\text{Vậy phương trình trên có tập nghiệm là }S=\left\{\dfrac{86}{7}\right\}\)
