Question

4^x + 4^x+2 = 272

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Answer 1

4^x + 4^x+2 = 272

<=> 4^x + 4^x.4² = 272

<=> 4^x ( 1 + 4² ) = 272

<=> 4^x = 16

<=> x = 2

Answer 2

\(4^x+4^{x+2}=272\)

\(\Rightarrow4^x+4^x.4^2=272\)

\(\Rightarrow4^x\left(1+4^2\right)=272\)

\(\Rightarrow4^x=\frac{272}{17}=16\)

\(\Rightarrow4^x=16=4^2\)

\(\Rightarrow x=2\)

Vậy: \(x=2\)

Answer 3

4^x + 4^x+2= 272

=> 4^x( 1+ 4² ) = 272

=> 4^x. 17 = 272

=> 4^x = 272:17

=> 4^x= 16 = 4²

=> x = 2

vậy x = 2

Answer 4

Ta có \(4^x+4^{x+2}=272\)

\(\Rightarrow4^x+4^x.16=272\)

\(\Rightarrow4^x.\left(1+16\right)=272\)

\(\Rightarrow4^x.17=272\)

\(\Rightarrow4^x=16\)

\(\Rightarrow4^x=4^2\)

\(\Rightarrow x=2\)

Vậy x=2

 

Answer 5

4^x + 4^x+2= 272

4^x(1+4²) = 272

4^x.17 = 272

4^x = 272:17

4^x = 16

4^x =4²

x =2

Answer 6

4^x + 4^x+2 = 272

=> 4^x + 4^x.4²=272

=> 4^x.(1+4²) =272

=>4^x.17=272

=> 4^x=16

=> x=2