Question

4. Tìm x

a. \(\left|x-2\right|=2x\)

b. \(\left|x+5,9\right|=3x\)

c. \(\left|4,03-x\right|=5x\)

d. \(\left|x+2\right|x+\left|x+4\right|=4x\)

Answer 1

a: \(\Leftrightarrow\left\{{}\begin{matrix}x>=0\\\left(2x-x+2\right)\left(2x+x-2\right)=0\end{matrix}\right.\Leftrightarrow x=\dfrac{2}{3}\)

b: \(\Leftrightarrow\left\{{}\begin{matrix}x>=0\\\left(3x-x-5.9\right)\left(3x+x+5.9\right)=0\end{matrix}\right.\Leftrightarrow x=2.95\)

c: \(\Leftrightarrow\left\{{}\begin{matrix}x>=0\\\left(5x-4.03+x\right)\left(5x+4.03-x\right)=0\end{matrix}\right.\Leftrightarrow x=\dfrac{403}{600}\)