Question

√(4-√12)

Answer 1

-8

Answer 2

=0.73205080756

Answer 3

$\sqrt{4-\sqrt{12}}\\=\sqrt{4-2\sqrt 3}\\=\sqrt{3-2\sqrt 3+1}\\=\sqrt{(\sqrt 3-1)^2}\\=|\sqrt 3-1|\\=\sqrt 3-1(vì\,\,\sqrt 3-1>0)$

Answer 4

√ 4 − √ 12 = √ 4 − 2 √ 3 = √ 3 − 2 √ 3 + 1 = √ ( √ 3 − 1 ) 2 = | √ 3 − 1 | = √ 3 − 1 ( v i ˋ √ 3 − 1 > 0 )