3x=4y=> \(\dfrac{x}{3}=\)\(\dfrac{y}{4}\)=>\(\dfrac{x^2}{3^2}=\) \(\dfrac{y^2}{4^2}\)
áp dụng tính chất dãy tỉ số bằng nhau ta có:
\(\dfrac{x^2}{3^2}=\)\(\dfrac{y^2}{4^2}\)=\(\dfrac{x^2+y^2}{9+16}=\)\(\dfrac{400}{25}=\)16
+) \(\dfrac{x^2}{9}=16\Rightarrow x^2=9.16=144\Rightarrow x=\pm12\)
+) \(\dfrac{y^2}{16}=16\Rightarrow y^2=16.16=256\Rightarrow y=\pm16\)
vẬY X=12 ,y=16 hoặc x=-12,y=-16