$3x^2-11x+6=0$
$\to 3x^2-9x-2x+6=0$
$\to 3x(x-3)-2(x-3)=0$
$\to (x-3)(3x-2)=0$
$\to \left[ \begin{array}{l}3x-2=0\\x-3=0\end{array} \right.$
$\to \left[ \begin{array}{l}x=\dfrac{2}{3}\\x=3\end{array} \right.$
Vậy phương trình có tập nghiệm $S=\{3,\dfrac{2}{3}\}$
Ta có: \(3x^2-11x+6=0\)
\(\Leftrightarrow3x^2-9x-2x+6=0\)
\(\Leftrightarrow3x\left(x-3\right)-2\left(x-3\right)=0\)
\(\Leftrightarrow\left(x-3\right)\left(3x-2\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x-3=0\\3x-2=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\3x=2\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=\dfrac{2}{3}\end{matrix}\right.\)
Vậy: \(S=\left\{3;\dfrac{2}{3}\right\}\)
