Question

3x-2.(2x-1)=1\(\frac{1}{3}\)

\(\frac{x+4}{20}\)=\(\frac{5}{x+4}\)

Answer 1

a) \(3x-2\left(2x-1\right)=1\frac{1}{3}\)

\(\Leftrightarrow3x-4x+2=1\frac{1}{3}\)

\(\Leftrightarrow-x=-\frac{2}{3}\)

\(\Leftrightarrow x=\frac{2}{3}\)

Vậy ....

b) \(\frac{x+4}{20}=\frac{5}{x+4}\)

\(\Leftrightarrow\left(x+4\right)^2=100\)

\(\Leftrightarrow\left[{}\begin{matrix}x+4=10\\x+4=-10\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=6\\x=-14\end{matrix}\right.\)

Vậy \(x\in\left\{6;-14\right\}\)