Đặt \(A=\left(3+1\right)\left(3^2+1\right)\left(3^4+1\right)\left(3^6+1\right)\left(3^8+1\right)\left(3^{16}+1\right)\)
\(\Leftrightarrow2A=\left(3-1\right)\left(3+1\right)\left(3^2+1\right)\left(3^4+1\right)\left(3^6+1\right)\left(3^8+1\right)\left(3^{16}+1\right)\)\(\Leftrightarrow2A=\left(3^2-1\right)\left(3^2+1\right)\left(3^4+1\right)\left(3^6+1\right)\left(3^8+1\right)\left(3^{16}+1\right)\)
\(\Leftrightarrow2A=\left(3^4-1\right)\left(3^4+1\right)\left(3^6+1\right)\left(3^8+1\right)\left(3^{16}+1\right)\)
\(\Leftrightarrow2A=\left(3^8-1\right)\left(3^8+1\right)\left(3^{16}+1\right)\left(3^6+1\right)\)
\(\Leftrightarrow2A=\left(3^{16}-1\right)\left(3^{16}+1\right)\left(3^6+1\right)\)
\(\Leftrightarrow2A=\left(3^{32}-1\right)\left(3^6+1\right)\)
\(\Leftrightarrow A=\dfrac{\left(3^{32}-1\right)\left(3^6+1\right)}{2}\)
