\(3x-\dfrac{5}{4}=\dfrac{1}{2}\\ 3x=\dfrac{1}{2}+\dfrac{5}{4}\\ 3x=\dfrac{7}{4}\\ x=\dfrac{7}{4}:3\\ x=\dfrac{7}{12}\)
\(3x-\dfrac{5}{4}=\dfrac{1}{2}\)
\(3x=\dfrac{2}{4}+\dfrac{5}{4}\)
\(3x=\dfrac{7}{4}\)
\(x=\dfrac{7}{4}:3\)
\(x=\dfrac{7}{12}\)
Lời giải:
$\frac{3x-5}{4}=\frac{1}{2}$
$3x-5=4.\frac{1}{2}=2$
$3x=5+2=7$
$x=\frac{7}{3}$