Question

(2x-√9/4)^2=1/√625

Answer 1

\(\left(2x-\sqrt{\dfrac{9}{4}}\right)^2=\dfrac{1}{\sqrt{625}}\)

\(\Leftrightarrow\left(2x-\dfrac{3}{2}\right)^2=\dfrac{1}{25}\)

\(\Leftrightarrow\left[{}\begin{matrix}2x-\dfrac{3}{2}=\sqrt{\dfrac{1}{25}}\\2x-\dfrac{3}{2}=-\sqrt{\dfrac{1}{25}}\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}2x-\dfrac{3}{2}=\dfrac{1}{5}\\2x-\dfrac{3}{2}=-\dfrac{1}{5}\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}2x=\dfrac{17}{10}\\2x=\dfrac{13}{10}\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{17}{20}\\x=\dfrac{13}{20}\end{matrix}\right.\)

Vậy ..

Answer 2

\(\left(2x-\sqrt{\dfrac{9}{4}}\right)^2=\dfrac{1}{\sqrt{625}}\\ \Leftrightarrow\left(2x-\dfrac{3}{2}\right)^2=\dfrac{1}{25}\\ \Leftrightarrow\left[{}\begin{matrix}2x-\dfrac{3}{2}=\dfrac{1}{5}\\2x-\dfrac{3}{2}=-\dfrac{1}{5}\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=\dfrac{17}{20}\\x=\dfrac{13}{20}\end{matrix}\right.\)

Answer 3

(2x -√\(\dfrac{9}{4}\))²=\(\dfrac{1}{\sqrt{625}}\)

(2x- \(\dfrac{3}{2}\))² = \(\dfrac{1}{25}\)

2x²- (\(\dfrac{3}{2}\))² = \(\dfrac{1}{25}\)

2x² = \(\dfrac{1}{25}\)-(\(\dfrac{3}{2}\))²

2x² = \(\dfrac{-221}{100}\)

x² = \(\dfrac{-221}{200}\)

x = √\(\dfrac{-221}{200}\)