\(\left(2x-\sqrt{\dfrac{9}{4}}\right)^2=\dfrac{1}{\sqrt{625}}\)
\(\Leftrightarrow\left(2x-\dfrac{3}{2}\right)^2=\dfrac{1}{25}\)
\(\Rightarrow\left[{}\begin{matrix}2x-\dfrac{3}{2}=\dfrac{1}{5}\\2x-\dfrac{3}{2}=-\dfrac{1}{5}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{17}{20}\\x=\dfrac{13}{20}\end{matrix}\right.\)
(2x-√9/4)^2=1/√625
tinh
\(\dfrac{\dfrac{1}{9}-\dfrac{1}{7}-\dfrac{1}{11}}{\dfrac{4}{9}-\dfrac{4}{7}-\dfrac{4}{11}}+\dfrac{3\left(\dfrac{1}{5}-\dfrac{1}{25}-\dfrac{1}{125}-\dfrac{1}{625}\right)}{4\left(\dfrac{1}{5}-\dfrac{1}{25}-\dfrac{1}{125}-\dfrac{1}{625}\right)}\)
Tìm số tự nhiên x
a) \(\dfrac{1}{27}.9^x=3^x\)
b) \(2^{x-1}+5.2^{x-2}=\dfrac{7}{32}\)
c) \(\left(\dfrac{4}{5}\right)^{2x+7}=\dfrac{625}{256}\)
d) \(\left(4x-3\right)^4=\left(4x-3\right)^2\)
2 TÌM X BIẾT
a, (5x+1)^2 = 36/49
b, (12/25)^x =(5/3)^2 -(-3/5)^4
c, (-3/4)^ 3x-1 = 256/81
d, 172 .x ^2 -7^9 :98^3 =2^3
e,5^x .(5^3)^2 =625
f, (x-2/9)^3 =(2/3)^6
a, \(\frac{-5}{8}-x:3\frac{5}{6}+7\frac{3}{4}=-2\)
b,\(\frac{3}{4}:2\frac{4}{9}-\left|-3x+2\frac{2}{3}\right|=\frac{3}{4}\)
c, \(\left(\frac{4}{5}\right)^{2x+5}=\frac{256}{625}\)
d,\(\left(x-\frac{2}{15}\right)^3=\frac{8}{125}\)
Thức hiện phép tính:
\(\frac{\frac{1}{9}-\frac{1}{7}-\frac{1}{11}}{\frac{4}{9}-\frac{4}{7}-\frac{4}{11}}+\frac{\frac{3}{5}-\frac{3}{25}-\frac{3}{125}-\frac{3}{625}}{\frac{4}{5}-\frac{4}{626}-\frac{4}{125}-\frac{4}{25}}\)
Bài 2 Tìm x biết :
a) -5 | x - 3 | + | 1/2x + 4 | = 7|
b) | 2x + 1 | - 4 | 5 - x | = 9
c) | 9 - | x | = 8
d) - | 2x + 4/3 | - 11 - x | = -7/3
2 VIẾT DƯỚI DẠNG LUỸ THỪA CỦA 1 SỐ NGUYÊN:
a, 123: (3^4 .6^4)
b, 5^4 . 125 .(2.5)^-5 .0,04
c, (3/7)^5 .(7/3)^-1 -(5/3)^6 : (343/625)^-2
Tìm x biết rằng:
e) \(5^{x+2_{ }^{ }}\) = \(625\);
f) \(\left(x-1\right)^{x+2}\) = \(\left(x+1\right)^{x+4}\);
g) \(\left(2x-1\right)^3=-8\)
h) \(\frac{1}{4}\).\(\frac{2}{6}.\frac{3}{8}.\frac{4}{10}.\frac{5}{12}...\frac{30}{62}.\frac{31}{64}\) = \(2^x\)
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