\(\left|2x-27\right|^{2017}\ge0\\ \left(3y+10\right)^{2018}\ge0\\ \left|2x-27\right|^{2017}+\left(3y+10\right)^{2018}=0\\ \Rightarrow\left\{{}\begin{matrix}2x-27=0\\3y+10=0\end{matrix}\right.\\ \Rightarrow\left\{{}\begin{matrix}x=\dfrac{27}{2}\\y=-\dfrac{10}{3}\end{matrix}\right.\)